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5=60(1/x)
We move all terms to the left:
5-(60(1/x))=0
Domain of the equation: x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(60(+1/x))+5=0
We multiply all the terms by the denominator
-(60(+1+5*x))=0
We calculate terms in parentheses: -(60(+1+5*x)), so:We get rid of parentheses
60(+1+5*x)
We add all the numbers together, and all the variables
60(5x+1)
We multiply parentheses
300x+60
Back to the equation:
-(300x+60)
-300x-60=0
We move all terms containing x to the left, all other terms to the right
-300x=60
x=60/-300
x=-1/5
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