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5=60x(1/x)
We move all terms to the left:
5-(60x(1/x))=0
Domain of the equation: x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(60x(+1/x))+5=0
We multiply all the terms by the denominator
-(60x(+1+5*x))=0
We calculate terms in parentheses: -(60x(+1+5*x)), so:We get rid of parentheses
60x(+1+5*x)
We add all the numbers together, and all the variables
60x(5x+1)
We multiply parentheses
300x^2+60x
Back to the equation:
-(300x^2+60x)
-300x^2-60x=0
a = -300; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·(-300)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:x_{1}=\frac{-b-\sqrt{\Delta}}{2a}x_{2}=\frac{-b+\sqrt{\Delta}}{2a}\sqrt{\Delta}=\sqrt{3600}=60x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*-300}=\frac{0}{-600} =0x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*-300}=\frac{120}{-600} =-1/5
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