5=7/2(10x+35)

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Solution for 5=7/2(10x+35) equation: 



5=7/2(10x+35)

We move all terms to the left:

5-(7/2(10x+35))=0



Domain of the equation: 2(10x+35))!=0

x∈R



We multiply all the terms by the denominator


-(7+5*2(10x+35))=0



We calculate terms in parentheses: -(7+5*2(10x+35)), so:

7+5*2(10x+35)

determiningTheFunctionDomain
5*2(10x+35)+7

Wy multiply elements

10x(1+7

Back to the equation:

-(10x(1+7)



We add all the numbers together, and all the variables

-(10x8=0

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