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5=8-3(3x-5)
We move all terms to the left:
5-(8-3(3x-5))=0
We calculate terms in parentheses: -(8-3(3x-5)), so:We get rid of parentheses
8-3(3x-5)
determiningTheFunctionDomain -3(3x-5)+8
We multiply parentheses
-9x+15+8
We add all the numbers together, and all the variables
-9x+23
Back to the equation:
-(-9x+23)
9x-23+5=0
We add all the numbers together, and all the variables
9x-18=0
We move all terms containing x to the left, all other terms to the right
9x=18
x=18/9
x=2
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