5=ln(x/1)

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Solution for 5=ln(x/1) equation: 


D( x )

x/1 <= 0

x/1 <= 0

x/1 <= 0

x <= 0

x+0 <= 0 // - 0

x <= 0

x in (0:+oo)

5 = ln(x/1) // - ln(x/1)

5-ln(x/1) = 0

5-ln(x) = 0

5-ln(x) = 0 // - 5

-ln(x) = -5

-ln(x) = -5 // * -1

ln(x) = ln(e^5)

x = e^5

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