5=z+47/4

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Solution for 5=z+47/4 equation:



5=z+47/4
We move all terms to the left:
5-(z+47/4)=0
We add all the numbers together, and all the variables
-(+z+47/4)+5=0
We get rid of parentheses
-z+5-47/4=0
We multiply all the terms by the denominator
-z*4-47+5*4=0
We add all the numbers together, and all the variables
-z*4-27=0
Wy multiply elements
-4z-27=0
We move all terms containing z to the left, all other terms to the right
-4z=27
z=27/-4
z=-6+3/4

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