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5X*3X=100
We move all terms to the left:
5X*3X-(100)=0
Wy multiply elements
15X^2-100=0
a = 15; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·15·(-100)
Δ = 6000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6000}=\sqrt{400*15}=\sqrt{400}*\sqrt{15}=20\sqrt{15}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{15}}{2*15}=\frac{0-20\sqrt{15}}{30} =-\frac{20\sqrt{15}}{30} =-\frac{2\sqrt{15}}{3} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{15}}{2*15}=\frac{0+20\sqrt{15}}{30} =\frac{20\sqrt{15}}{30} =\frac{2\sqrt{15}}{3} $
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