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5a(4a+15)2=0
We multiply parentheses
40a^2+150a=0
a = 40; b = 150; c = 0;
Δ = b2-4ac
Δ = 1502-4·40·0
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-150}{2*40}=\frac{-300}{80} =-3+3/4 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+150}{2*40}=\frac{0}{80} =0 $
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