5a+(4-a)=9-(a-6)

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Solution for 5a+(4-a)=9-(a-6) equation: 



5a+(4-a)=9-(a-6)

We move all terms to the left:

5a+(4-a)-(9-(a-6))=0

We add all the numbers together, and all the variables

5a+(-1a+4)-(9-(a-6))=0

We get rid of parentheses

5a-1a-(9-(a-6))+4=0



We calculate terms in parentheses: -(9-(a-6)), so:

9-(a-6)

determiningTheFunctionDomain
-(a-6)+9

We get rid of parentheses

-a+6+9

We add all the numbers together, and all the variables

-1a+15

Back to the equation:

-(-1a+15)



We add all the numbers together, and all the variables

4a-(-1a+15)+4=0

We get rid of parentheses

4a+1a-15+4=0

We add all the numbers together, and all the variables

5a-11=0

We move all terms containing a to the left, all other terms to the right

5a=11

a=11/5

a=2+1/5

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