5a-1(a+3)=1/3(9a+18)-5

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Solution for 5a-1(a+3)=1/3(9a+18)-5 equation: 



5a-1(a+3)=1/3(9a+18)-5

We move all terms to the left:

5a-1(a+3)-(1/3(9a+18)-5)=0



Domain of the equation: 3(9a+18)-5)!=0

a∈R



We multiply all the terms by the denominator


5a*3(9a+18)-5)-(1(a+3))*3(9a+18)-5)-(1=0

We add all the numbers together, and all the variables

5a*3(9a+18)-5)-(1(a+3))*3(9a=0

Wy multiply elements

15a^2(9-5)-(1(a+3))*3(9a=0

We add all the numbers together, and all the variables

15a^24-(1(a+3))*3(9a=0

We do not support eapression: a^24

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