5a-10=3(a+1)+19a+5

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Solution for 5a-10=3(a+1)+19a+5 equation: 



5a-10=3(a+1)+19a+5

We move all terms to the left:

5a-10-(3(a+1)+19a+5)=0



We calculate terms in parentheses: -(3(a+1)+19a+5), so:

3(a+1)+19a+5

We add all the numbers together, and all the variables

19a+3(a+1)+5

We multiply parentheses

19a+3a+3+5

We add all the numbers together, and all the variables

22a+8

Back to the equation:

-(22a+8)



We get rid of parentheses

5a-22a-8-10=0

We add all the numbers together, and all the variables

-17a-18=0

We move all terms containing a to the left, all other terms to the right

-17a=18

a=18/-17

a=-1+1/17

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