5a-2(-7a-10)=128

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Solution for 5a-2(-7a-10)=128 equation: 



5a-2(-7a-10)=128

We move all terms to the left:

5a-2(-7a-10)-(128)=0

We multiply parentheses

5a+14a+20-128=0

We add all the numbers together, and all the variables

19a-108=0

We move all terms containing a to the left, all other terms to the right

19a=108

a=108/19

a=5+13/19

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