5a-4=2(a+1)+10a+4

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Solution for 5a-4=2(a+1)+10a+4 equation: 



5a-4=2(a+1)+10a+4

We move all terms to the left:

5a-4-(2(a+1)+10a+4)=0



We calculate terms in parentheses: -(2(a+1)+10a+4), so:

2(a+1)+10a+4

We add all the numbers together, and all the variables

10a+2(a+1)+4

We multiply parentheses

10a+2a+2+4

We add all the numbers together, and all the variables

12a+6

Back to the equation:

-(12a+6)



We get rid of parentheses

5a-12a-6-4=0

We add all the numbers together, and all the variables

-7a-10=0

We move all terms containing a to the left, all other terms to the right

-7a=10

a=10/-7

a=-1+3/7

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