5a-4=3(a+1)+10a+2

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Solution for 5a-4=3(a+1)+10a+2 equation: 



5a-4=3(a+1)+10a+2

We move all terms to the left:

5a-4-(3(a+1)+10a+2)=0



We calculate terms in parentheses: -(3(a+1)+10a+2), so:

3(a+1)+10a+2

We add all the numbers together, and all the variables

10a+3(a+1)+2

We multiply parentheses

10a+3a+3+2

We add all the numbers together, and all the variables

13a+5

Back to the equation:

-(13a+5)



We get rid of parentheses

5a-13a-5-4=0

We add all the numbers together, and all the variables

-8a-9=0

We move all terms containing a to the left, all other terms to the right

-8a=9

a=9/-8

a=-1+1/8

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