5a-4=3(a+1)+9a+1

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Solution for 5a-4=3(a+1)+9a+1 equation: 



5a-4=3(a+1)+9a+1

We move all terms to the left:

5a-4-(3(a+1)+9a+1)=0



We calculate terms in parentheses: -(3(a+1)+9a+1), so:

3(a+1)+9a+1

We add all the numbers together, and all the variables

9a+3(a+1)+1

We multiply parentheses

9a+3a+3+1

We add all the numbers together, and all the variables

12a+4

Back to the equation:

-(12a+4)



We get rid of parentheses

5a-12a-4-4=0

We add all the numbers together, and all the variables

-7a-8=0

We move all terms containing a to the left, all other terms to the right

-7a=8

a=8/-7

a=-1+1/7

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