5a-5=2(a+1)+11a+4

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Solution for 5a-5=2(a+1)+11a+4 equation: 



5a-5=2(a+1)+11a+4

We move all terms to the left:

5a-5-(2(a+1)+11a+4)=0



We calculate terms in parentheses: -(2(a+1)+11a+4), so:

2(a+1)+11a+4

We add all the numbers together, and all the variables

11a+2(a+1)+4

We multiply parentheses

11a+2a+2+4

We add all the numbers together, and all the variables

13a+6

Back to the equation:

-(13a+6)



We get rid of parentheses

5a-13a-6-5=0

We add all the numbers together, and all the variables

-8a-11=0

We move all terms containing a to the left, all other terms to the right

-8a=11

a=11/-8

a=-1+3/8

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