5a-5=7(a+1)+14a+7

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Solution for 5a-5=7(a+1)+14a+7 equation: 



5a-5=7(a+1)+14a+7

We move all terms to the left:

5a-5-(7(a+1)+14a+7)=0



We calculate terms in parentheses: -(7(a+1)+14a+7), so:

7(a+1)+14a+7

We add all the numbers together, and all the variables

14a+7(a+1)+7

We multiply parentheses

14a+7a+7+7

We add all the numbers together, and all the variables

21a+14

Back to the equation:

-(21a+14)



We get rid of parentheses

5a-21a-14-5=0

We add all the numbers together, and all the variables

-16a-19=0

We move all terms containing a to the left, all other terms to the right

-16a=19

a=19/-16

a=-1+3/16

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