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5a-6=10-(-a)
We move all terms to the left:
5a-6-(10-(-a))=0
We add all the numbers together, and all the variables
5a-(10-(-1a))-6=0
We calculate terms in parentheses: -(10-(-1a)), so:We get rid of parentheses
10-(-1a)
determiningTheFunctionDomain -(-1a)+10
We get rid of parentheses
1a+10
We add all the numbers together, and all the variables
a+10
Back to the equation:
-(a+10)
5a-a-10-6=0
We add all the numbers together, and all the variables
4a-16=0
We move all terms containing a to the left, all other terms to the right
4a=16
a=16/4
a=4
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