5a-7=4(a+1)+12a+1

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Solution for 5a-7=4(a+1)+12a+1 equation: 



5a-7=4(a+1)+12a+1

We move all terms to the left:

5a-7-(4(a+1)+12a+1)=0



We calculate terms in parentheses: -(4(a+1)+12a+1), so:

4(a+1)+12a+1

We add all the numbers together, and all the variables

12a+4(a+1)+1

We multiply parentheses

12a+4a+4+1

We add all the numbers together, and all the variables

16a+5

Back to the equation:

-(16a+5)



We get rid of parentheses

5a-16a-5-7=0

We add all the numbers together, and all the variables

-11a-12=0

We move all terms containing a to the left, all other terms to the right

-11a=12

a=12/-11

a=-1+1/11

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