5a2+-6a+-32=0

Solution for 5a2+-6a+-32=0 equation:

5a^2+-6a+-32=0

We add all the numbers together, and all the variables

5a^2-6a=0

a = 5; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·5·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*5}=\frac{0}{10}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*5}=\frac{12}{10}
=1+1/5
$