5a=(-3)+(3/5a)

Solution for 5a=(-3)+(3/5a) equation:

5a=(-3)+(3/5a)

We move all terms to the left:

5a-((-3)+(3/5a))=0


Domain of the equation: 5a))!=0

a!=0/1

a!=0

a∈R


We add all the numbers together, and all the variables

5a-((-3)+(+3/5a))=0

We multiply all the terms by the denominator


5a*5a))-((+3-3)+(=0

We add all the numbers together, and all the variables

5a*5a))-(0+(=0

Wy multiply elements

25a^2=0

a = 25; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·25·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{50}=0$