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5b(9+b)=0
We add all the numbers together, and all the variables
5b(b+9)=0
We multiply parentheses
5b^2+45b=0
a = 5; b = 45; c = 0;
Δ = b2-4ac
Δ = 452-4·5·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-45}{2*5}=\frac{-90}{10} =-9 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+45}{2*5}=\frac{0}{10} =0 $
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