5b(b=5)

Solution for 5b(b=5) equation:

5b(b=5)

We move all terms to the left:

5b(b-(5))=0

We multiply parentheses

5b^2-25b=0

a = 5; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·5·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*5}=\frac{0}{10}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*5}=\frac{50}{10}
=5
$