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5b*5b-5b-1=0
We add all the numbers together, and all the variables
-5b+5b*5b-1=0
Wy multiply elements
25b^2-5b-1=0
a = 25; b = -5; c = -1;
Δ = b2-4ac
Δ = -52-4·25·(-1)
Δ = 125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{125}=\sqrt{25*5}=\sqrt{25}*\sqrt{5}=5\sqrt{5}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{5}}{2*25}=\frac{5-5\sqrt{5}}{50} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{5}}{2*25}=\frac{5+5\sqrt{5}}{50} $
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