5b+2(3b-6)=27-2b

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Solution for 5b+2(3b-6)=27-2b equation: 



5b+2(3b-6)=27-2b

We move all terms to the left:

5b+2(3b-6)-(27-2b)=0

We add all the numbers together, and all the variables

5b+2(3b-6)-(-2b+27)=0

We multiply parentheses

5b+6b-(-2b+27)-12=0

We get rid of parentheses

5b+6b+2b-27-12=0

We add all the numbers together, and all the variables

13b-39=0

We move all terms containing b to the left, all other terms to the right

13b=39

b=39/13

b=3

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