5b+3(b-4)=2(y+2)

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Solution for 5b+3(b-4)=2(y+2) equation:


Simplifying
5b + 3(b + -4) = 2(y + 2)

Reorder the terms:
5b + 3(-4 + b) = 2(y + 2)
5b + (-4 * 3 + b * 3) = 2(y + 2)
5b + (-12 + 3b) = 2(y + 2)

Reorder the terms:
-12 + 5b + 3b = 2(y + 2)

Combine like terms: 5b + 3b = 8b
-12 + 8b = 2(y + 2)

Reorder the terms:
-12 + 8b = 2(2 + y)
-12 + 8b = (2 * 2 + y * 2)
-12 + 8b = (4 + 2y)

Solving
-12 + 8b = 4 + 2y

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 8b = 4 + 12 + 2y

Combine like terms: -12 + 12 = 0
0 + 8b = 4 + 12 + 2y
8b = 4 + 12 + 2y

Combine like terms: 4 + 12 = 16
8b = 16 + 2y

Divide each side by '8'.
b = 2 + 0.25y

Simplifying
b = 2 + 0.25y

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