5b+3=2+7(b+6)

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Solution for 5b+3=2+7(b+6) equation: 



5b+3=2+7(b+6)

We move all terms to the left:

5b+3-(2+7(b+6))=0



We calculate terms in parentheses: -(2+7(b+6)), so:

2+7(b+6)

determiningTheFunctionDomain
7(b+6)+2

We multiply parentheses

7b+42+2

We add all the numbers together, and all the variables

7b+44

Back to the equation:

-(7b+44)



We get rid of parentheses

5b-7b-44+3=0

We add all the numbers together, and all the variables

-2b-41=0

We move all terms containing b to the left, all other terms to the right

-2b=41

b=41/-2

b=-20+1/2

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