5b+4(b-2)=3(3b-3)+1

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Solution for 5b+4(b-2)=3(3b-3)+1 equation:


Simplifying
5b + 4(b + -2) = 3(3b + -3) + 1

Reorder the terms:
5b + 4(-2 + b) = 3(3b + -3) + 1
5b + (-2 * 4 + b * 4) = 3(3b + -3) + 1
5b + (-8 + 4b) = 3(3b + -3) + 1

Reorder the terms:
-8 + 5b + 4b = 3(3b + -3) + 1

Combine like terms: 5b + 4b = 9b
-8 + 9b = 3(3b + -3) + 1

Reorder the terms:
-8 + 9b = 3(-3 + 3b) + 1
-8 + 9b = (-3 * 3 + 3b * 3) + 1
-8 + 9b = (-9 + 9b) + 1

Reorder the terms:
-8 + 9b = -9 + 1 + 9b

Combine like terms: -9 + 1 = -8
-8 + 9b = -8 + 9b

Add '8' to each side of the equation.
-8 + 8 + 9b = -8 + 8 + 9b

Combine like terms: -8 + 8 = 0
0 + 9b = -8 + 8 + 9b
9b = -8 + 8 + 9b

Combine like terms: -8 + 8 = 0
9b = 0 + 9b
9b = 9b

Add '-9b' to each side of the equation.
9b + -9b = 9b + -9b

Combine like terms: 9b + -9b = 0
0 = 9b + -9b

Combine like terms: 9b + -9b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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