5b-10=8+8(b+8)

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Solution for 5b-10=8+8(b+8) equation: 



5b-10=8+8(b+8)

We move all terms to the left:

5b-10-(8+8(b+8))=0



We calculate terms in parentheses: -(8+8(b+8)), so:

8+8(b+8)

determiningTheFunctionDomain
8(b+8)+8

We multiply parentheses

8b+64+8

We add all the numbers together, and all the variables

8b+72

Back to the equation:

-(8b+72)



We get rid of parentheses

5b-8b-72-10=0

We add all the numbers together, and all the variables

-3b-82=0

We move all terms containing b to the left, all other terms to the right

-3b=82

b=82/-3

b=-27+1/3

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