5b-11(9+8b)=-6-11(b+3)

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Solution for 5b-11(9+8b)=-6-11(b+3) equation: 



5b-11(9+8b)=-6-11(b+3)

We move all terms to the left:

5b-11(9+8b)-(-6-11(b+3))=0

We add all the numbers together, and all the variables

5b-11(8b+9)-(-6-11(b+3))=0

We multiply parentheses

5b-88b-(-6-11(b+3))-99=0



We calculate terms in parentheses: -(-6-11(b+3)), so:

-6-11(b+3)

determiningTheFunctionDomain
-11(b+3)-6

We multiply parentheses

-11b-33-6

We add all the numbers together, and all the variables

-11b-39

Back to the equation:

-(-11b-39)



We add all the numbers together, and all the variables

-83b-(-11b-39)-99=0

We get rid of parentheses

-83b+11b+39-99=0

We add all the numbers together, and all the variables

-72b-60=0

We move all terms containing b to the left, all other terms to the right

-72b=60

b=60/-72

b=-5/6

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