5b-5(3b-2)=70

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Solution for 5b-5(3b-2)=70 equation: 



5b-5(3b-2)=70

We move all terms to the left:

5b-5(3b-2)-(70)=0

We multiply parentheses

5b-15b+10-70=0

We add all the numbers together, and all the variables

-10b-60=0

We move all terms containing b to the left, all other terms to the right

-10b=60

b=60/-10

b=-6

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