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5b/10+2/10=13
We move all terms to the left:
5b/10+2/10-(13)=0
determiningTheFunctionDomain 5b/10-13+2/10=0
We multiply all the terms by the denominator
5b+2-13*10=0
We add all the numbers together, and all the variables
5b-128=0
We move all terms containing b to the left, all other terms to the right
5b=128
b=128/5
b=25+3/5
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