5b=27+8(b-3)

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Solution for 5b=27+8(b-3) equation: 



5b=27+8(b-3)

We move all terms to the left:

5b-(27+8(b-3))=0



We calculate terms in parentheses: -(27+8(b-3)), so:

27+8(b-3)

determiningTheFunctionDomain
8(b-3)+27

We multiply parentheses

8b-24+27

We add all the numbers together, and all the variables

8b+3

Back to the equation:

-(8b+3)



We get rid of parentheses

5b-8b-3=0

We add all the numbers together, and all the variables

-3b-3=0

We move all terms containing b to the left, all other terms to the right

-3b=3

b=3/-3

b=-1

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