5c(c+1)+6=0

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Solution for 5c(c+1)+6=0 equation: 



5c(c+1)+6=0

We multiply parentheses

5c^2+5c+6=0

a = 5; b = 5; c = +6;
Δ = b2-4ac
Δ = 52-4·5·6
Δ = -95
Delta is less than zero, so there is no solution for the equation

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