5c(c-2)=6-3c

Solution for 5c(c-2)=6-3c equation:

5c(c-2)=6-3c

We move all terms to the left:

5c(c-2)-(6-3c)=0

We add all the numbers together, and all the variables

5c(c-2)-(-3c+6)=0

We multiply parentheses

5c^2-10c-(-3c+6)=0

We get rid of parentheses

5c^2-10c+3c-6=0

We add all the numbers together, and all the variables

5c^2-7c-6=0

a = 5; b = -7; c = -6;
Δ = b2-4ac
Δ = -72-4·5·(-6)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-13}{2*5}=\frac{-6}{10}
=-3/5
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+13}{2*5}=\frac{20}{10}
=2
$