5c+(-12)=28

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Solution for 5c+(-12)=28 equation: 



5c+(-12)=28

We move all terms to the left:

5c+(-12)-(28)=0

determiningTheFunctionDomain
5c-28+(-12)=0

We add all the numbers together, and all the variables

5c-40=0

We move all terms containing c to the left, all other terms to the right

5c=40

c=40/5

c=8

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