5c+12+3c=4(2c+8)

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Solution for 5c+12+3c=4(2c+8) equation: 



5c+12+3c=4(2c+8)

We move all terms to the left:

5c+12+3c-(4(2c+8))=0

We add all the numbers together, and all the variables

8c-(4(2c+8))+12=0



We calculate terms in parentheses: -(4(2c+8)), so:

4(2c+8)

We multiply parentheses

8c+32

Back to the equation:

-(8c+32)



We get rid of parentheses

8c-8c-32+12=0

We add all the numbers together, and all the variables

-20!=0

There is no solution for this equation

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