5c+2(1-c)=2(2c-1)

Solution for 5c+2(1-c)=2(2c-1) equation:

Simplifying
5c + 2(1 + -1c) = 2(2c + -1)
5c + (1 * 2 + -1c * 2) = 2(2c + -1)
5c + (2 + -2c) = 2(2c + -1)

Reorder the terms:
2 + 5c + -2c = 2(2c + -1)

Combine like terms: 5c + -2c = 3c
2 + 3c = 2(2c + -1)

Reorder the terms:
2 + 3c = 2(-1 + 2c)
2 + 3c = (-1 * 2 + 2c * 2)
2 + 3c = (-2 + 4c)

Solving
2 + 3c = -2 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
2 + 3c + -4c = -2 + 4c + -4c

Combine like terms: 3c + -4c = -1c
2 + -1c = -2 + 4c + -4c

Combine like terms: 4c + -4c = 0
2 + -1c = -2 + 0
2 + -1c = -2

Add '-2' to each side of the equation.
2 + -2 + -1c = -2 + -2

Combine like terms: 2 + -2 = 0
0 + -1c = -2 + -2
-1c = -2 + -2

Combine like terms: -2 + -2 = -4
-1c = -4

Divide each side by '-1'.
c = 4

Simplifying
c = 4