5c+2(11-4c)=13(3c-2)

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Solution for 5c+2(11-4c)=13(3c-2) equation:


Simplifying
5c + 2(11 + -4c) = 13(3c + -2)
5c + (11 * 2 + -4c * 2) = 13(3c + -2)
5c + (22 + -8c) = 13(3c + -2)

Reorder the terms:
22 + 5c + -8c = 13(3c + -2)

Combine like terms: 5c + -8c = -3c
22 + -3c = 13(3c + -2)

Reorder the terms:
22 + -3c = 13(-2 + 3c)
22 + -3c = (-2 * 13 + 3c * 13)
22 + -3c = (-26 + 39c)

Solving
22 + -3c = -26 + 39c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-39c' to each side of the equation.
22 + -3c + -39c = -26 + 39c + -39c

Combine like terms: -3c + -39c = -42c
22 + -42c = -26 + 39c + -39c

Combine like terms: 39c + -39c = 0
22 + -42c = -26 + 0
22 + -42c = -26

Add '-22' to each side of the equation.
22 + -22 + -42c = -26 + -22

Combine like terms: 22 + -22 = 0
0 + -42c = -26 + -22
-42c = -26 + -22

Combine like terms: -26 + -22 = -48
-42c = -48

Divide each side by '-42'.
c = 1.142857143

Simplifying
c = 1.142857143

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