5c+2(6c+4)=229

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Solution for 5c+2(6c+4)=229 equation: 



5c+2(6c+4)=229

We move all terms to the left:

5c+2(6c+4)-(229)=0

We multiply parentheses

5c+12c+8-229=0

We add all the numbers together, and all the variables

17c-221=0

We move all terms containing c to the left, all other terms to the right

17c=221

c=221/17

c=13

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