5c+3-3c=2(c+3)-5

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Solution for 5c+3-3c=2(c+3)-5 equation: 



5c+3-3c=2(c+3)-5

We move all terms to the left:

5c+3-3c-(2(c+3)-5)=0

We add all the numbers together, and all the variables

2c-(2(c+3)-5)+3=0



We calculate terms in parentheses: -(2(c+3)-5), so:

2(c+3)-5

We multiply parentheses

2c+6-5

We add all the numbers together, and all the variables

2c+1

Back to the equation:

-(2c+1)



We get rid of parentheses

2c-2c-1+3=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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