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5c+3=2(c-5)
We move all terms to the left:
5c+3-(2(c-5))=0
We calculate terms in parentheses: -(2(c-5)), so:We get rid of parentheses
2(c-5)
We multiply parentheses
2c-10
Back to the equation:
-(2c-10)
5c-2c+10+3=0
We add all the numbers together, and all the variables
3c+13=0
We move all terms containing c to the left, all other terms to the right
3c=-13
c=-13/3
c=-4+1/3
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