5c+4c+2=5c+2(2c+1)

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Solution for 5c+4c+2=5c+2(2c+1) equation: 



5c+4c+2=5c+2(2c+1)

We move all terms to the left:

5c+4c+2-(5c+2(2c+1))=0

We add all the numbers together, and all the variables

9c-(5c+2(2c+1))+2=0



We calculate terms in parentheses: -(5c+2(2c+1)), so:

5c+2(2c+1)

We multiply parentheses

5c+4c+2

We add all the numbers together, and all the variables

9c+2

Back to the equation:

-(9c+2)



We get rid of parentheses

9c-9c-2+2=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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