5c+4c+3=(7+2c)

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Solution for 5c+4c+3=(7+2c) equation: 



5c+4c+3=(7+2c)

We move all terms to the left:

5c+4c+3-((7+2c))=0

We add all the numbers together, and all the variables

5c+4c-((2c+7))+3=0

We add all the numbers together, and all the variables

9c-((2c+7))+3=0



We calculate terms in parentheses: -((2c+7)), so:

(2c+7)

We get rid of parentheses

2c+7

Back to the equation:

-(2c+7)



We get rid of parentheses

9c-2c-7+3=0

We add all the numbers together, and all the variables

7c-4=0

We move all terms containing c to the left, all other terms to the right

7c=4

c=4/7

c=4/7

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