5c+4c-5c+8c=48

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Solution for 5c+4c-5c+8c=48 equation: 



5c+4c-5c+8c=48

We move all terms to the left:

5c+4c-5c+8c-(48)=0

We add all the numbers together, and all the variables

12c-48=0

We move all terms containing c to the left, all other terms to the right

12c=48

c=48/12

c=4

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