5c+7c+3+1=4(3c+1)

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Solution for 5c+7c+3+1=4(3c+1) equation: 



5c+7c+3+1=4(3c+1)

We move all terms to the left:

5c+7c+3+1-(4(3c+1))=0

We add all the numbers together, and all the variables

12c-(4(3c+1))+4=0



We calculate terms in parentheses: -(4(3c+1)), so:

4(3c+1)

We multiply parentheses

12c+4

Back to the equation:

-(12c+4)



We get rid of parentheses

12c-12c-4+4=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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