5c-2(4c-9)=5+6(2-c)

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Solution for 5c-2(4c-9)=5+6(2-c) equation:



5c-2(4c-9)=5+6(2-c)
We move all terms to the left:
5c-2(4c-9)-(5+6(2-c))=0
We add all the numbers together, and all the variables
5c-2(4c-9)-(5+6(-1c+2))=0
We multiply parentheses
5c-8c-(5+6(-1c+2))+18=0
We calculate terms in parentheses: -(5+6(-1c+2)), so:
5+6(-1c+2)
determiningTheFunctionDomain 6(-1c+2)+5
We multiply parentheses
-6c+12+5
We add all the numbers together, and all the variables
-6c+17
Back to the equation:
-(-6c+17)
We add all the numbers together, and all the variables
-3c-(-6c+17)+18=0
We get rid of parentheses
-3c+6c-17+18=0
We add all the numbers together, and all the variables
3c+1=0
We move all terms containing c to the left, all other terms to the right
3c=-1
c=-1/3
c=-1/3

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