5c-2(c+2)=11-(2c+5)

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Solution for 5c-2(c+2)=11-(2c+5) equation: 



5c-2(c+2)=11-(2c+5)

We move all terms to the left:

5c-2(c+2)-(11-(2c+5))=0

We multiply parentheses

5c-2c-(11-(2c+5))-4=0



We calculate terms in parentheses: -(11-(2c+5)), so:

11-(2c+5)

determiningTheFunctionDomain
-(2c+5)+11

We get rid of parentheses

-2c-5+11

We add all the numbers together, and all the variables

-2c+6

Back to the equation:

-(-2c+6)



We add all the numbers together, and all the variables

3c-(-2c+6)-4=0

We get rid of parentheses

3c+2c-6-4=0

We add all the numbers together, and all the variables

5c-10=0

We move all terms containing c to the left, all other terms to the right

5c=10

c=10/5

c=2

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