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5c-2/c=-6
We move all terms to the left:
5c-2/c-(-6)=0
Domain of the equation: c!=0We add all the numbers together, and all the variables
c∈R
5c-2/c+6=0
We multiply all the terms by the denominator
5c*c+6*c-2=0
We add all the numbers together, and all the variables
6c+5c*c-2=0
Wy multiply elements
5c^2+6c-2=0
a = 5; b = 6; c = -2;
Δ = b2-4ac
Δ = 62-4·5·(-2)
Δ = 76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{76}=\sqrt{4*19}=\sqrt{4}*\sqrt{19}=2\sqrt{19}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{19}}{2*5}=\frac{-6-2\sqrt{19}}{10} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{19}}{2*5}=\frac{-6+2\sqrt{19}}{10} $
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