5c-2c+12=4(2c-7)

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Solution for 5c-2c+12=4(2c-7) equation:



5c-2c+12=4(2c-7)
We move all terms to the left:
5c-2c+12-(4(2c-7))=0
We add all the numbers together, and all the variables
3c-(4(2c-7))+12=0
We calculate terms in parentheses: -(4(2c-7)), so:
4(2c-7)
We multiply parentheses
8c-28
Back to the equation:
-(8c-28)
We get rid of parentheses
3c-8c+28+12=0
We add all the numbers together, and all the variables
-5c+40=0
We move all terms containing c to the left, all other terms to the right
-5c=-40
c=-40/-5
c=+8

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